THE NEW STUDENTS REFERENCE WORK 2157
Divide 8401 by 39.
This example differs from the preceding examples in that 215|f the second divisor figure is a large number. 39 is so much 39)8401 nearer 40 than 30, we must find the quotient figures by
78 comparing the first one or first two dividend figures with 4
60 as a trial divisor rather than 3.
39 4 is contained in 8, 2 times.
211 4 is contained in 6, once.
195 4 is contained in 21, 5 times.
16 remainder. Thus the quotient is 215 with a remainder of 16.
In general, if the second divisor figure is 1, 2, or 3, the first divisor figure is the trial divisor. If the second divisor figure is 7, 8, or 9, the trial divisor should be one more than the first divisor figure. If the second divisor figure is 4, 5, or 6, the trial divisor may be the first divisor figure, or one more than the first divisor figure.
Practice will show.
First. If the product is greater than the partial dividend, the quotient figure is too large.
Second. If the remainder is greater than the divisor, the quotient figure is too small.
Divide 26,874 by 44.
In an example of this kind care must be taken not to 610f omit the last 0 in the quotient.
44)26874 264
IT" 44
34 remainder.
8752^- 10=875 and 2 remainder. 8752^ 100= 87 and 52 remainder. 8752-f-1000= 8 and 752 remainder.
A number may be divided by 10, 100, 1000, etc., by cutting off as many dividend figures from the right, as there are ciphers on the right of the divisor. The figures cut off will be the remainder, the rest will be the quotient.
12,000^-30 is the same as 1200-^3.
Cutting off the same number of ciphers from the right of both divi<?*md and divisor, does not change the quotient.
