This page has been validated.
60
SUCCESSIVE CARRIAGE.
not exceed that of adding a single digit to another digit. If this could be accomplished it would render additions and subtractions with numbers having ten, twenty, fifty, or any number of figures, as rapid as those operations are with single figures.
Let us now examine the case in which there were several carriages. Its successive stages may be better explained, thus—
| 2648 | |
| 4584 | |
| Stages. | ——– |
| 1 Add units' figure = 4 | 2642 |
| 2 Carry | 1 |
| ——– | |
| 2652 | |
| 3 Add tens' figure = 8 | 8 |
| ——– | |
| 2632 | |
| 4 Carry | 1 |
| ——– | |
| 2732 | |
| 5 Add hundreds' figure = 5 | 5 |
| ——– | |
| 2232 | |
| 6 Carry | 1 |
| ——– | |
| 3232 | |
| 7 Add thousands' figure = 4 | 4 |
| ——– | |
| 7232 | |
| 8 Carry 0. There is no carr. |
Now if, as in this case, all the carriages were known, it would then be possible to make all the additions of digits at the same time, provided we could also record each carriage as it became due. We might then complete the addition by adding, at the same instant, each carriage in its proper place. The process would then stand thus:—
