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Models of the Aether.
329

there results

Take now the xz-averages of both members. The quantities u′/∂t, ∂u′/∂x, v, ∂p/∂x have zero averages; so the equation takes the form

,

if the symbol A is used to indicate that the xz-average is to be taken of the quantity following. Moreover, the incompressibility of the fluid is expressed by the equation

whence

.

When this is added to the preceding equation, the first and third pairs of terms of the second member vanish, since the x-average of any derivate Q/∂x vanishes if Q is finite for infinitely great values of x; and the equation thus becomes

(1)

From this it is seen that if the turbulent motion were to remain continually isotropic as at the beginning, f (y, t) would constantly retain its critical value f(y). In order to examine the deviation from isotropy, we shall determine A∂(u′v)/∂t, which may be done in the following way:—Multiplying the u- and v-equations of motion by v, u′ respectively, and adding, we have