# Page:EB1911 - Volume 17.djvu/1007

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988
[KINETICS
MECHANICS

body, called the invariable cone. At any point of this we have x: y:z = Ap. Bq: Cr, and the equation is therefore 2 2

<5>

The signs of the coellicients follow the same rule as in the case of (4). The possible forms of the invariable cone are indicated in fig. 80 by means of the intersections with a concentric spherical surface. In the critical case of

2 BT = 1' 2 the cone degenerates

into two planes. It appears

that if the body be sightly disturbed from a state of rotation

about the principal axis of

greatest or least moment, the

invariable cone will closely surround this axis, which will

therefore never deviate far

from the invariable line. If,

on the other hand, the body be

slightly disturbed from a state

of rotation about the mean axis

awide deviation willtake place.

of greatest or least moment is

reckoned as stable, a rotation about the mean axis as unstable. The question is greatly simplified when two of the principal moments are equal, say A=B. The polhode and herpolhode cones are then right circular, and the motion is “ processional ” according to the definition of § 18. If a be the inclination of the instantaneous axis to the axis of symmetry, B the inclination of the latter axis to the invariable line, we have I' cos;3=Cw cos a, I' sin 13 = Aw sin a, (6) FIG. So.

Hence a rotation about the axis

whence

tan /3 =-2 tan a. (7)

Hence B 2 a, and the circumstances are therefore those of the first or second case in fig. 78, according as A 2 C. If xl/ be the H - H C

3 c.

Fig. 81.

rate at which the plane HO] revolves about OH, we have ¢ sin aw

sinB

by § 18 (3). Also if 72 be the

C cos a

same ~ <8>

rate at which ] describes the

polhode, we have ip sin (5 -a) =X sin B, whence, sin (a-13)

X sin a. w' (9)

If the instantaneous axis only deviate slightly from the axis of symmetry the angles a, B are small, and X = (A-C) A, .o.>; the instantaneous axis therefore completes its revolution in the body in the period

21- = A - C w, (0

X — A . 1)

In the case of the earth it is inferred from the independent phenomenon of luni-solar precession that (C-A)/A= -00313. Hence if the earth's axis of rotation deviates slightly from the axis of figure, it should describe a cone about the latter in 320 sidereal days. This would cause a periodic variation in the latitude of any place on the earth's surface, as determined by astronomical methods. There appears to be evidence of a slight periodic variation of latitude, but the period would seem to be about fourteen months. The discrepancy is attributed to a defect of rigidity in the earth. The phenomenon is known as the Eulerian nutation, since it is supposed to come under the free rotations first discussed by Euler. § zo. Motion of a Solid of Revolution.-In the case of a solid of revolution, or (more generally) whenever there is kinetic symmetry about an axis through the mass—centre, or through a. fixed point O, a number of interesting problems can be treated almost directly from first principles. It frequently happens that the extraneous forces have zero moment about the axis of symmetry, as e.g. in the case of the flywheel of a gyroscope if we neglect the friction at the bearings. The angular velocity (r) about this axis is then constant. For we have seen that r is constant when there are no extraneous forces; and r is evidently not aHected by an instantaneous impulse which leaves the angular momentum Cr, about the axis of symmetry, unaltered. And a continuous force may be regarded as the limit of a succession of infinitesimal instantaneous impulses. Suppose, for example, that a Hywheel is rotating with angular velocity 11 about its axis, which is (say) horizontal, and that this axis is made to rotate with the angular velocity nk in the horizontal plane. The components of angular momentum about the axis of the flywheel and about the vertical will be Cn and A ¢ respectively, where A is the moment of inertia about any axis through the mass centre (or thgigugh the fixed point O) perpendicular to that of symmetry. If OK be the vector representing the former component < ->

at time t, the vector which represents it at time t-l-Bt will be OK', 6

equal to OK in magnitude and making with it an angle 650. Hence KH' (=Cn5p) will represent the change in this component due to the extraneous forces. Hence, so far as this component is concerned, the extraneous forces must supply a couple of moment Cntb in a vertical plane through the axis of the flywheel. If this couple be absent, the axis will be tilted out of the horizontal plane in such a sense that the direction of the spin n approximates to that of the azimuthal rota- K

tion ul/ The remaining constituent of, the extraneous forces is a couple AQ 0 about the vertical; this vanishes if gb is constant. If the axis of the flywheel make an angle 9 with the vertical, it is seen in like manner that the required couple in the vertical plane through the axis is Cn sin H gb. This matter can be strikingly illustrated with an ordinary gyroscope, e.g. by making the larger movable ring in fig. 37 rotate about its vertical diameter.-FIG.

82.

If the direction of the axis of kinetic symmetry be specified by means of the angular co-ordinates 0,111 of § 7, then considering the component velocities of the point C in iig. 83, which are 0 and sin 91/1 along and perpendicular to the meridian ZC, we see that the component angular velocities about the lines

OA', OB' are-sin 0 1,0 and 0 respectively. Hence if the principal moments of inertia at O be A, A, C, and if n be the constant angular velocity about the axis OC, the kinetic energy is given by

2T=A(@2-|-sin”0 552)-I-Cnz. i (I)

Again, the components of angular momentum about OC, OA' are Cn, ~A sin 0¢, and therefore the angular momentum (, u., say) about OZ is

p=A sin' 0 \$4-Cn cos H. (2)

We can hence deduce the condition of steady processional motion in a top. A solid of revolution is supposed to be free to turn about a fixed point O on its axis of symmetry, its mass centre G being in this axis at a distance h from O. In fig. 83 OZ is supposed to be vertical, and OC is the axis of the solid drawn in the direction OG. If 0 is constant the points C, A' will in timeét come to positions C", A” such that CC”=sin 0 61, b, A'A"= cos 6 51//, and the angular momentum about OB' will become Cn sin 6 6¢-A sin 6' //. cos 0 6¢. Equating this to M gh sin 0 iii, and dividing out by sin 0, we obtain A cos 0 1,52-Cn:/;+Mgh=o, (3)

as the condition in question. For given values of n and 0 we have two possible values of 1,0 provided n exceed a certain limit. With a very rapid spin, or (more precisely) with Cn large in comparison with 1/ (4AMgh cos 0), one value of 1,0 is small and the other large, viz. the two values are Mgh/Cn and Cn/A cos 0 approximately. The absence of g from the latter expression indicates that the circumstances of the rapid precession are very 