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A Tide TABLE h
North. South. Queensburgh, Iſle of wight 0 00
NBE SBW Aberdene, Rocheſter 0 45
NEBN SWBS Graves-end, Downs Scilly 1 30
NE SW Leith, St Andrews, Dundee 2 15
NEBE SWBW London, Tinmouth, Amſterd. 3 00
ENE WSW Berwick,Flamburghhead 3 45
EBN WBS Kingſaile, Baltimore,Uſhant 4 30
Newcastle, humber, Lizard 5 15
Eaſt weſt Briſtol, Plimouth, Hull 6 00
EBS WBN Waterford, Abermorick 6 45
ESE WNW Portruth, Milnford, Texel 7 30
SEBE NWBW Dublin, lamby, the Hague 8 15
SE NW Dumbar, Iſle of Man, Orkney 9 00
SEBS NWBN North and ſouth Foreland 9 4
SSE NNW Yarmouth, Dover, Harwich 10 30
SBE NBW Rye, Winchelſy, Culſhot 11 15
The Uſe.
Having known what Moon makes full Sea in any Port or Harbour, ( as you have a Table here of the moſt re- markable ) you muſt multiply the Moons age by 4,and di- vide the product by 5, the quotient will be hours, and the remainders will be 5 parts of an hour, ( every 5 part being 12') for the time of the Moons ſouthing, and ad- ding 24 thereto will be her northing; very near to which add the hours and minuts belonging to the point of flow- ing, and then ſeek the Moons age in this Table, under
Moons age h, ' the moons age and to-
1 : 14 : 16 : 29 0 : 0 wards the right hand
2 : 13 : 17 : 28 0 : 5 you have the hours and
3 : 12 : 18 : 27 0 : 10 minuts to be ſubtracted
4 : 11 : 19 : 26 0 : 20 from the former ſum, so
5 : 10 : 20 : 25 0 : 30 the remainder is true
6 : 9 : 21 : 24 0 : 45 time of full sea.
7 : 8 : 22 : 23 1 : 00 Example.
I demand full sea
Leith the 6 day of the Moons age? Anſwer, multiply 6 by
4, product is 24, which divide by 5, quotient is 4 and 4/5
48' to which ad 2 h 15' belonging to NEBN or SWE
for Leith, ſum is 5 h. from which ſubtract 45' found in the
laſt Table, remainder is 4 h, 18' true time of full sea,
Leith required. F I N I S.
