TABLE OF ELEVATION FOR MAXIM ·303 USING AMMUNITION GIVING 2,000 F.S.
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| Range. | Angles of elevation on the|
| | Maxim gun. |
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| 200 yards | 0 4·0 0 1 |
| 300 " | 0 9·5 " |
| 400 " | 0 17·0 " |
| 500 " | 0 25·5 " |
| 600 " | 0 35·5 " |
| 700 " | 0 45·5 " |
| 800 " | 0 57·5 " |
| 900 " | 1 10·5 " |
|1,000 " | 1 25·5 " |
|1,100 " | 1 41·5 " |
|1,200 " | 1 57·5 " |
|1,300 " | 2 16·5 " |
|1,400 " | 2 37·5 " |
|1,500 " | 2 59·5 " |
|1,600 " | 3 22·5 " |
|1,700 " | 3 47·5 " |
|1,800 " | 4 14·5 " |
|1,900 " | 4 43·5 " |
|2,000 " | 5 14·5 " |
|2,100 " | 5 42·0 " |
|2,200 " | 6 22·0 " |
|2,300 " | 6 59·0 " |
|2,400 " | 7 40·0 " |
|2,500 " | 8 25·0 " |
|2,600 " | 9 16·0 " |
|2,700 " | 10 18·0 " |
|2,800 " | 11 18·0 " |
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What is required is the angle of quadrant elevation to be put on the gun in order that the shots may strike the target at a known range. From range table obtain angle of tangent elevation; now if the target is below the guns we must subtract the angle of sight (m), if the target is above the guns we must add the angle of sight (m) to obtain correct angle of quadrant elevation.
To obtain angle of sight m
(1) When target is visible from the immediate
