98 Notes.
THE TABLE.
| Numbers. | Logarithms. | ||||||||
| A | 1.000000 | a | 0.0000000 | ||||||
| B | 10.000000 | b | 1.0000000 | ||||||
| C | = | √(AB) | = | 3.162277 | c | = | 12(a + b) | = | 0.5000000 |
| D | = | √(BC) | = | 5.623413 | d | = | 12(b + c) | = | 0.7500000 |
| E | = | √(CD) | = | 4.216964 | e | = | 12(c + d) | = | 0.6250000 |
| F | = | √(DE) | = | 4.869674 | f | = | 12(d + e) | = | 0.6875000 |
| G | = | √(DF) | = | 5.232991 | g | = | 12(d + f) | = | 0.7187500 |
| H | = | √(FG) | = | 5.048065 | h | = | 12(f + g) | = | 0.7031250 |
| I | = | √(FH) | = | 4.958069 | i | = | 12(f + h) | = | 0.6953125 |
| K | = | √(HI) | = | 5.002865 | k | = | 12(h + i) | = | 0.6992187 |
| L | = | √(IK) | = | 4.980416 | l | = | 12(i + k) | = | 0.6972656 |
| M | = | √(KL) | = | 4.991627 | m | = | 12(k + l) | = | 0.6982421 |
| N | = | √(KM) | = | 4.997240 | n | = | 12(k + m) | = | 0.6987304 |
| O | = | √(KN) | = | 5.000052 | o | = | 12(k + n) | = | 0.6987304 |
| P | = | √(NO) | = | 4.998647 | p | = | 12(n + o) | = | 0.6988525 |
| Q | = | √(OP) | = | 4.999350 | q | = | 12(o + p) | = | 0.6989135 |
| R | = | √(OP) | = | 4.999701 | r | = | 12(o + p) | = | 0.6989440 |
| S | = | √(OR) | = | 4.999876 | s | = | 12(o + r) | = | 0.6989592 |
| T | = | √(OS) | = | 4.999963 | t | = | 12(o + s) | = | 0.6989668 |
| V | = | √(OT) | = | 5.000008 | v | = | 12(o + t) | = | 0.6989707 |
| W | = | √(TV) | = | 4.999984 | w | = | 12(t + v) | = | 0.6989687 |
| X | = | √(VW) | = | 4.999997 | x | = | 12(v + w) | = | 0.6989697 |
| Y | = | √(VX) | = | 5.000003 | y | = | 12(v + x) | = | 0.6989702 |
| Z | = | √(XY) | = | 5.000000 | z | = | 12(x + y) | = | 0.6989700 |
III.
In the description of the third method, on pages 53-54, it is explained that when log. 1 = 0 and log. 10 is assumed equal to unit with a number of cyphers annexed, a close approximation to the logarithm of any given number may be obtained by finding the number of places in the result produced by raising the given number to a power equal to the assumed logarithm of 10, As an example, Napier mentions that, assuming log.
10
