THE RESOLVING OF BACON'S BILITERAL REDUCED TO THREE SYMBOLS IN A NUMBER CIPHER

Place in their relative order as appearing in the original arrangement the selected symbols of the Biliteral:

a a a a a

a a a a b

&c

Then place opposite each the number arrived at by the application of odd and even figures to represent the numerical values of the symbols "a" and "b."

Thus aaaaa will be as shown 9

aaaab will be as shown 72

aaaba will be as shown 521

and so on. Then put in sequence of numerical value. We shall then have: 0. 9. 18. 27. 36. 45. 54. 63. 72. 81. 125. 143. 161. 216. 234. 252. 323. 341. 414. 432. 521. 612. An analysis shows that of these there are two of one figure; eight of two figures; and twelve of three figures. Now as regards the latter seriesâ€”the symbols composed of three figuresâ€”we will find that if we add together the component figures of each of those which begins and ends with an even number they will tot up to nine; but that the total of each of those commencing

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