NEW MATH
words and music by Tom Lehrer
You can't take three from two, |
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Now, that actually is not the answer that I had in mind, because the book that I got this problem out of wants you to do it in base eight. But don't panic! Base eight is just like base ten really - if you're missing two fingers! Shall we have a go at it? Hang on… | |||||||
You can't take three from two, |
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New Math
Words and Music by Tom Lehrer
342 |
You can't take three from two, |
![\header {
title = ""
tagline = "" % no footer
}
\score { { <<
\new ChordNames \chordmode {
\set chordChanges = ##t
\partial 8*3 s4. |
f2 |
f2 |
c8:7 b:7 bes:7 a:7 |
a2:7 |
d:m |
d4:m7 g:7 |
c4. a8:7 |
a2:7 |
d:m |
d:m |
es |
es |
g:7 |
g:7 |
b4/c c |
s2
}
{ \new Staff <<
\relative c'' {
\language "english"
\time 2/4
\set Score.tempoHideNote = ##t \tempo 8 = 260
\set Staff.midiInstrument = #"lead 6 (voice)"
\partial 8*3 ^\markup{REFRAIN} g8[ a b] |
r c4. |
a4 r |
g8[ gf f e] ~ e4 r8 e |
f[ e f e] |
f16 e8 f16 ~ f e f8 |
g4. e8 ~ | e4 f8 g |
a f4. |
r8 a gs a |
bf g4. |
r4 bf |
b!8 a4 g8 |
b4. b8 |
b c4 r8 |
r4 r \bar "|."
}
\addlyrics {
Hoo -- ray for new math,
New -- hoo -- hoo math,
It won't do you a bit of good to re -- view math.
It's so sim -- ple, so ver -- y sim -- ple, that on -- ly a child can do it!
}
{ \new PianoStaff <<
{ \new Staff <<
{ \new Voice <<
\relative c'' {
\language "english"
\set Staff.midiInstrument = "piano"
\stemUp
\partial 8*3 g8[ a b] |
r c4. |
a4 r |
<g e>8[ <gf ef> <f d> <e! cs>] ~ | <e cs>4 r8 e |
<f d>[ <e cs> <f d> <e cs>] |
<f d c!>16 e8 <f d b>16 ~ <f d b>16 e16 <f d>8 |
<g e>4. <e cs g>8 ~ | <e cs g>4 f8 g |
a f4. |
r8 a gs a |
bf g4 r8 |
r4 bf |
b!8 a ~ a g |
b4. b8 |
b c4 r8 |
r4 r4 |
}
>> }
{ \new Voice <<
\relative c'' {
\language "english"
\set Staff.midiInstrument = "piano"
\stemDown
\partial 8*3 s4. |
r8 <a f>[ r <a f>] |
r <f c>[ r <f c>] |
s2 | s2 |
s2 |
s2 |
s2 | s2 |
r8 <d g>[ r <d g>] |
r <f d>[ r <f d>] |
r <ef bf>[ r <ef bf>] |
r <ef bf>[ r <ef bf>] |
r <f b!>[ r <f b!>] |
r <g f>[ r <f d>] |
<fs ds> <g e>4 r8 |
s2 |
}
>> }
>> }
{ \new Staff <<
\relative c {
\language "english"
\set Staff.midiInstrument = "piano"
\clef bass
\partial 8*3 r8 r4 |
f8[ r c] r |
f[ r c] r |
bf'[ a af g] ~ | g a,[ b cs] |
d[ r a] r |
d r g, b |
c[ b bf a ~] |
a a[ b! cs] |
d[ r a] r |
d[ r a] r |
ef'[ r bf] r |
ef[ r bf] r |
d[ r a] r |
d[ r a] r |
c4. g8 |
c,-. r r4 |
}
>> }
>> }
>> }
>> }
\layout { }
\midi { }
}](http://upload.wikimedia.org/score/m/1/m16gzdlyiu61koqh6c979tf3pir71h6/m16gzdly.png)
342eight |
Now, actually, that is not the answer that I had in mind, because the book that I got this problem out of wants you to do it in base eight. But don't panic. Base eight is just like base ten really — if you're missing two fingers. Shall we have a go at it?
You can't take three from two,
Sixty-four? "How did sixty-four get into it?" I hear you cry. Well, sixty-four is eight squared, don't you see? (Well, you ask a silly question, and you get a silly answer.)
From the three you then use one |